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The decreasing order of size of isoelectronic series $K^{+} \cdot {Ca}^{2 +} \cdot {Cl}^{-}$ and $S^{2 -}$ is

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$K^{+} > {Ca}^{2} > S^{2 -} > {Cl}^{-}$

$K^{+} > {Ca}^{2 +} > {Cl}^{-} > S^{2 -}$

${Ca}^{2 -} > K^{+} > {Cl}^{-} > S^{2 -}$

$S^{2 -} > {Cl}^{-} > K^{+} > {Ca}^{2 +}$

answer is D.

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Detailed Solution

$S^{2 -} > {Cl}^{-} > K^{+} > {Ca}^{2 +} .$

As negative charge increases size increases, As positive charge increases size decreases.

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