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The decreasing order of the strength of bases. $O H^{-}$ , $N H_{2}^{-}$ , $C H \equiv C^{-}$ and $C H_{3} O^{-}$

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$N H_{2}^{-} > C_{2} H^{-} > O H^{-} > C H_{3} O^{-}$

$O H^{-} > C_{2} H^{-} > C H_{3} O^{-} > N H_{2}^{-}$

$C_{2} H^{-} > N H_{2}^{Θ} > O H^{Θ} > C H_{3} O^{-}$

$C H_{3} O^{-} > C_{2} H^{-} > N H_{2}^{-} > O H^{-}$

answer is A.

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Detailed Solution

$H_{2} O$ , $N H_{3}$ , $C_{2} H_{2}$ , $C H_{3} O H$ are acid conjugates
$∴$ acidic strength : $C H_{3} O H > H_{2} O > C_{2} H_{2} > N H_{3}$
Basic strength : $C H_{3} O^{-} < O H^{-} < C_{2} H^{-} < N H_{2}^{-}$

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