Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The decreasing values of bond angles from NH3 to SbH3 down the group 15 of the periodic table is due to

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

increasing bp–bp repulsion

b

increasing p-orbital character in sp3

c

decreasing lp-bp repulsion

d

decreasing electronegativity of central atom

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The H - M - H bond angle is less than the original 1090, tetrahedral bond angle (H -N -H) in Ammonia 1060
because of greater repulsion between one pair an a on pair than between two bond pairs of electrons. Because electro-negativity of M decreases from N to Bi, the bond pair lie farther away from the central atom, and the lone pair causes greater distortion of bond angle. Thus H-P-H bond in Phosphine.
 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
The decreasing values of bond angles from NH3 to SbH3 down the group 15 of the periodic table is due to