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Q.

The degree of dissociation of water at $25^{0}$ c is $1.9 x 10^{- 9}$ and density is $1.0 g c m^{- 3}$ The ionization constant $(K_{a})$ for water is nearly

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a

$1.0 x 10^{- 14}$

b

$1.0 x 10^{- 16}$

c

$1.0 x 10^{- 8}$

d

$1.8 x 10^{- 16}$

answer is B.

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Detailed Solution

Concentration of water $= \frac{1000}{18} = 55.55$

$[H^{+}] = C α = 55.55 x 1.9 x 10^{- 9} = 1.055 x 10^{- 7} M$

$k_{a} = \frac{[H^{+}] [O H^{-}]}{[H_{2} O]} = \frac{{(1.055 x 10^{- 7})}^{2}}{55.55} \approx 1.8 x 10^{- 16}$

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