The degree of hardness of water containing 1.20g of MgSO4 per litre of water in ppm (in terms ofmass of CaCO3) —— .

DOH= wt of salt in CaCO3 x 106w of water in grams DOH=1 x 1061000 =1000

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The degree of hardness of water containing 1.20g of MgSO₄ per litre of water in ppm (in terms of
mass of CaCO₃) —— .

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answer is 1000.

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$DOH = \frac{wt of salt i n C a C O_{3} x 10^{6}}{w of water in grams} DOH = \frac{1_{} x 10^{6}}{1000} = 1000$

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