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The density (in ${g mL}^{- 1}$ ) of a 3.60M sulphuric acid solution that is 29% $H_{2} {SO}_{4}$ (molar mass = ${98 g mol}^{- 1}$ ) by mass will be

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1.45

1.64

1.88

1.22

answer is D.

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Detailed Solution

$\begin{array}{l} M = \frac{x % \times d \times 10}{m o l . w t} \Rightarrow d = \frac{M \times m o l . w t}{x % \times 10} \\ = \frac{3.6 \times 98}{29 \times 10} = 1.22 \end{array}$

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