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The density of 1 M solution of a compound ' X ' is 1.25 g\mL^-1. The correct option for the molality of solution is (Molar mass of compound X=85 g ) :

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1.165 m

0.858 m

0.705 m

1.208 m

answer is D.

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Detailed Solution

$\begin{array}{l} m = \frac{1000 \times M}{1000 \times d - {MM}_{w}} \\ m = \frac{1000 \times 1}{1000 \times 1.25 - 1 \times 85} \\ m = \frac{1000}{1165} = 0.858 \end{array}$

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