The density of 3 M solution of NaCl is 1.0 g mL^-1. Molality of the solution is ___________ x 10^-2 m (Nearest integer).
Given: Mole mass of Na and Cl is 23 and 35.5 g mol^-1 respectively.

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answer is 364.

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Detailed Solution

n = 3 moles
Weight of solute = 3 x 58.5 = 175.5 g
Weight of solvent = 100 - 175.5 = 824.5 g
$\begin{array}{l} m = \frac{n}{W_{(kg)}} \\ = \frac{3}{824.5} \times 1000 = 3.64 . \end{array}$

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