The density of a 56.0% by weight aqueous solution of 1-propanol (CH₃CH₂CH₂OH) is 0.8975 g/cm³. What is the mole fraction of the compound ?

Mass of solution =100 g
Mass of solute = 56 g
 moles of solute $=\frac{56}{60}=0.93$
Mass of solvent = 44 g
moles of solvent = $=\frac{44}{18}=2.44$
${\mathrm{X}}_{\mathrm{Solute} }=\frac{0.93}{0.93+2.44}=\frac{0.93}{3.37}=0.276$