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Q.

The density of a gas (molar mass = 124 g mol^-1) at 1 atm and 620 K is

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a

$2.44 g {dm}^{- 3}$

b

$2.64 g {cm}^{- 3}$

c

$2.84 g {dm}^{- 3}$

d

$3.02 g {cm}^{- 3}$

answer is C.

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Detailed Solution

$ρ = \frac{p M}{R T} = \frac{(1 atm) (124 g {mol}^{- 1})}{(0.082 {dm}^{3} atm K^{- 1} {mol}^{- 1}) (620 K)} = 2.44 g {dm}^{- 3}$

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