Q.

The density of a pure substance A whose atoms pack in cubic close pack arrangement is 1 gm/cc. If B atoms can occupy tetrahedral void without distortions and they occupy all the tetrahedral voids, then what is the density of resulting solid m gm/cc?

[Given : MA = 30 amu, MB = 50 amu]

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a

1.33

b

5.33

c

4.33

d

2.33

answer is A.

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Detailed Solution

The density can be given as,

d=nMVNA

Here, we have,

V=4×301×NA

Thus, the value of density,

d=(4×30+8×50)VNA=520120=4.33

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