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The density of Ag is $10.5 g {cm}^{- 3}$ . The quantity of electricity needed to plate an area $100 {cm}^{2}$ to a thickness of $10^{- 2} cm$ by carrying out the electrolysis of ${AgNO}_{3}$ solution is

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6782 C

9382 C

4691 C

answer is C.

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Detailed Solution

$Q = I t = \frac{v_{e} F m}{M} = \frac{v_{e} F (ρ V)}{M} = \frac{(1) (96500 C {mol}^{- 1}) (10.5 g {cm}^{- 3}) (100 \times 10^{- 2} {cm}^{3})}{(108 g {mol}^{- 1})} = 9382 C$

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