The density of air is $0.001293 g / c m^{3}$ at 1 atm and $273 K$ . Identify which of the following statement is correct?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Vapour density and molecular weight cannot be determined.

Vapour density is $0.001293 g / c m^{3} .$

Molecular weight is $28.96 .$

Vapour density is $14.48 .$

answer is A, B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given,

Density of air $0.001293 g / c m^{3}$

Pressure $= 1 a t m$

Temperature $= 273 K$

The vapour density and the molecular weight is found as,

$M.W = 0.001293 \times 22400$

$= 28.96$

$V.D = 14.48$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test