Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

The density of air is 0.001293 g/cm3 at 1 atm and 273 K. Identify which of the following statement is correct?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

Vapour density is 14.48.

b

Molecular weight is 28.96.

c

Vapour density is 0.001293 g/cm3.

d

Vapour density and molecular weight cannot be determined.

answer is A, B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given,

Density of air 0.001293 g/cm3

Pressure = 1 atm

Temperature = 273 K

The vapour density and the molecular weight is found as,

 M.W =0.001293×22400

=28.96

 V.D =14.48

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon