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Q.

The density of newly discovered planet is twice that of the earth. the acceleration due to g at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R and the radius of the planet is R1 then what is the value of RR1.

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answer is 2.

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Detailed Solution

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g=GMR2=G43πR3δR2g∝Rδg1∝R1δ1g1=2δgg1=1,RR1=2

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