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Q.

The density of solid argon (Ar = 40 g/mol) is 1.68 g/mL at 40 K. If the argon atom is assumed to be a sphere of radius = 1.50 × 10-8 cm, what % of solid Ar is apparently empty space?

 

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a

35.64 

b

74%

c

64.36

d

None of these

answer is B.

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Detailed Solution

Volume of all atoms in 1.68 g

 Argon =1.6840×NA×43×π×1.5×10−83=0.3564

Volume of solid argon = 1 cm3

% Empty space - (1 - 0.3564) × 100 = 64.36

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