The density of the atmosphere at sea level is 1.29 kg/m³. Assume that it does not change with altitude. Then how high would the atmosphere extend?

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3 km

7 km

8 km

9 km

answer is C.

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Detailed Solution

$\begin{array}{l} ρ = 1 .29 kg / m^{2}; P = ρgh \\ 1 .013 \times 10^{5} = 1 .29 \times 9 .8 \times h \\ h = \frac{1 .013 \times 10^{5}}{1 .29 \times 9 .8} = 8 km \end{array}$

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