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The density $(ρ)$ versus pressure (P) of a given mass of an ideal gas is shown at two temperatures $T_{1}$ and $T_{2}$ may be

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$T_{2} > T_{1}$

$T_{1} = T_{2}$

All the three are possible

$T_{1} > T_{2}$

answer is B.

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Detailed Solution

According to ideal gas equation PV = nRT

$PV = \frac{m}{M} RT \Rightarrow P = \frac{ρRT}{M} \Rightarrow \frac{ρ}{P} \propto \frac{1}{T}$

Here, $\frac{ρ}{P}$ represent the slope of graph.

Hence, $T_{2} > T_{1}$

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