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Q.

The density $(in g {mL}^{- 1})$ of a 3.60 M sulphuric acid solution that is 29% $(H_{2} {SO}_{4} molar mass = 98 g {mol}^{- 1})$ by mass will be:

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a

1.45

b

1.64

c

1.22

d

1.88

answer is A.

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Detailed Solution

$Molarity of solution = \frac{Moles of H_{2} {SO}_{4}}{Volume of solution(ml)} \times 1000$

$(M = 3.60)$

$\begin{array}{l} \frac{\frac{29}{98}}{\frac{100}{d}} \times 1000 = 3.60 \\ d = 1.22 g / ml . \end{array}$

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