Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The derivative of F(x)=x2x31logtdt(x>0)=

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

13logx12logx

b

13logx

c

3x23logx

d

(logx)1x(x1)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

F(x)=x2x31logtdt(x>0)

Newton Leibnitz formula :

ddx(ϕ(x)Ψ(x)f(t)dt=f(Ψ(x))ddx(Ψ(x))f(ϕ(x))ddx(ϕ(x)))

=1logx33x21logx22x

=3x23logx2x2logx

=x2logxxlogx=x(x1)logx=x(x1)(logx)1.

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring