The descending order of magnitudes of the vectors A=i-j2, B=i+2k, C=3i+k, D=i+3j-k is

A=1 B=5 C=10 D=1+9+1=11 A<B<C<D

A=1 B=5 C=10 D=1+9+1=11 A<B<C<D

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The descending order of magnitudes of the vectors $A = \frac{i - j}{\sqrt{2}}, B = i + 2 k, C = 3 i + k, D = i + 3 j - k$ is

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D > C > B > A

A > B > C > D

D < B < C < A

D < A < C < B

answer is A.

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$|A| = 1 |B| = \sqrt{5} |C| = \sqrt{10} |D| = \sqrt{1 + 9 + 1} = \sqrt{11} |A| < |B| < |C| < |D|$

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