Q.

The diagonals of a square are equal and bisect each other at an angle of ____.


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Detailed Solution

The diagonals of a square are equal and bisect each other at an angle of 90°.
Show that the diagonals of a square are equal and bisect each other at  right angles Let the diagonals of a square ABCD are equal and bisect each other.
Therefore, we have,
OA = OC
BA= BC (Sides of a square are equal)
OB = BO (Common)
By SSS congruency criterion, we have,
ΔAOBΔCOB   We know corresponding sides of congruent triangles are equal.
AOB =COB   (1)   Using the linear pair property, we have,
AOB+COB=180° AOB+AOB=180°   from eq. (1) 2AOB =180° AOB = 90°   Therefore, the diagonals of a square are equal and bisect each other at an angle of 90 °  .
Hence, the answer is 90 °  .
 
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The diagonals of a square are equal and bisect each other at an angle of ____.