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The diagram shows an AC circuit with two voltage sources of same frequency. Find out the value of current I shown in the fig.

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$I = \frac{V_{0} \sin (ωt)}{R}$

$I = \frac{- 3 V_{0} \cos ωt}{R}$

$I = \frac{V_{0} \cos ωt}{R}$

$I = \frac{V_{0} \cos (ωt + π / 2)}{R}$

answer is D.

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Detailed Solution

$\begin{array}{l} {ΔV}_{R} = 2 V_{0} \cos (ωt + π) - V_{0} \cos (ωt) \\ = (- 2 V_{0} - V_{0}) \cos (ωt) ∴ I = (\frac{- 3 V_{0}}{R}) \cos (ωt) \end{array}$

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