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Q.

The diamagnetic compounds are

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a

${HgCl}_{2}$

b

CuCl

c

${TiO}_{2}$

d

All the above

answer is D.

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Detailed Solution

In HgCl₂, the electronic configuration of ${Hg}^{2 +}$ is $[Xe] 4 f^{14} 5 d^{10} .$ As there is no unpaired electrons in ${Hg}^{2 +},$ therefore HgCl₂ is diamagnetic.
The oxidation state of Cu in CuCl is +1 and its outer electronic configuration becomes $3 d^{10} .$ Because of having paired electrons, it is diamagnetic.
The oxidation of Ti in TiO₂ is +4 and its electronic configuration becomes [Ar]. Therefore, it is diamagnetic.

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