The diameter of a cylinder is measured using a Vernier calipers with no zero error. While measuring diameter of a cylinder, it is found that the zero of Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. Vernier scale has 50 divisions whose total length is equivalent to 2.45 cm. The closest division of the Vernier scale that almost coincides with a main scale division is 23^rd VSD but this 23^rd VSD actually falls slightly to the right of the main scale division. The diameter of cylinder may be (each MSD = 0.05 cm)

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51.246 mm

51.242 mm

51.238 mm

51.236 mm

answer is A, B.

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Detailed Solution

We see that 49 MSD = 50 VSD
$\Rightarrow L . C = \frac{1}{50} M S D = 0.01 m m$
If 24^th division is coinciding exactly.
Reading = (51 mm) + 23 (L.C) = 51.24 mm.
But 23^rd division is just to the right of MSD. So actual length is greater than 51 mm + 23 (L.C) but less than 51 mm + 24 (L.C)