Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

The diameter of a thin wire is measured by using a screw gauge having 100 divisions on circular scale. When spindle of screw gauge is touched to anvil,  then zero of circular scale lies 6 division above the reference line of main scale. Now, when wire is kept between spindle and anvil then 30th division of circular scale exactly coincides with the reference line of main scale as shown in the figure. The distance between two successive divisions of main scale is 0.1 mm. The measured diameter of wire is found to be  5.XYZ mm ,where X,Y and Z are non negative single digit integers. Find the value of  X+Y+Z  (pitch of the screw gauge is 0.1mm)
Question Image

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 9.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Pitch = 0.1mm, N = 100
Least count  =0.1100=0.001mm
Negative zero error =6×0.001=0.006mm
Reading of screw gauge =(50×0.1)mm+(30×0.001)mm=5.03mm
Measured value =(5.03+0.006)mm=5.036mm

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
The diameter of a thin wire is measured by using a screw gauge having 100 divisions on circular scale. When spindle of screw gauge is touched to anvil,  then zero of circular scale lies 6 division above the reference line of main scale. Now, when wire is kept between spindle and anvil then 30th division of circular scale exactly coincides with the reference line of main scale as shown in the figure. The distance between two successive divisions of main scale is 0.1 mm. The measured diameter of wire is found to be  5.XYZ mm ,where X,Y and Z are non negative single digit integers. Find the value of  X+Y+Z  (pitch of the screw gauge is 0.1mm)