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The diameter of an objective of a telescope, which can just resolve two stars situated at angular displacement of 10^-4 degree, should be (λ=5000 A⁰)

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35 m

35 cm

35 mm

24 cm

answer is B.

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Detailed Solution

$\Delta \theta = \frac{{1.22\lambda }}{a}{10^{ - 4}} \times \frac{\pi }{{180}} = \frac{{1.22 \times 5000 \times {{10}^{ - 10}}}}{a}\$

$a = 34.93 \times {10^{ - 2}}m = 35cm\$

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