The diameter of an objective of a telescope,which can just resolve two stars situated at angular displacement of 10-4 degree, should be $λ = 5000 A^{0}$ )

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35 m

35 cm

35 mm

24cm

answer is B.

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Detailed Solution

$\begin{array}{l} Δθ = \frac{1 .22 λ}{a}; 10^{- 4} \times \frac{π}{180} = \frac{1 .22 \times 5000 \times 10^{- 10}}{a} \\ a = 34 .93 \times 10^{2} m = 35 cm \end{array}$

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