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Q.

The  diameter of drop of water is 0.2 cm. The work done  in breaking one drop into 1000 equal  droplets will be (surface tension of water = 7×10−2 N/m)

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a

5.92×10−6J

b

1.92×10−6J

c

7.9×10−6J

d

2.92×10−6J

answer is A.

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Detailed Solution

w=4πr2T[n13−1]:n=1000

w=7.9×10−6J

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