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The diameter of the roller $120 cm$ long is $84 cm$ . If it takes 500 complete revolutions to level a playground, then find the cost of leveling at the rate of 30 paise per $m 2$ .

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Rs .475.21

Rs .475.20

Rs .425.20

Rs .465.20

answer is B.

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Detailed Solution

Given- The diameter of the roller

120 cm

long is

84 cm

. It takes 500 complete revolutions to level a playground.

h = 120 cm d = 84 c m r = 842 = 42 c m

.
To determine the cost of leveling at the rate of 30 paise or Rs.

\frac{30}{100}

per

m 2

.
Therefore,

Area covered by the roller in one revolution = curved surface area of the roller =2 π rh

= 2227 (42) (120) = 2217607 = 31680 cm 2

Now,

Cost of levelling the playground = 158430100 = Rs .475.20

.
Thus, the cost of leveling the playground is

Rs .475.20

.
Hence, option 2 is the correct option.

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