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The diameters of the ends of a frustum of a cone are 32cm and 20 cm. If its slant height is 10cm, then its lateral surface area is

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321 π c m^{2}

300 π c m^{2}

260 π c m^{2}

250 π c m^{2}

answer is C.

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Detailed Solution

R = 16 c m, ​ r = 10 ​ c m, l = 10 c m

LSA of frustum $= π L (R + r)$

$= π \times 10 (16 + 10)$

$= 260 π c m^{2}$

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