The difference between $Δ H$ and $Δ U (Δ H - Δ U),$ when the combustion of one mole of heptane ( $l$ ) is carried out at a temperature T, is equal to

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$3 R T$

$4 R T$

$- 4 R T$

$- 3 R T$

answer is C.

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Detailed Solution

$\begin{array}{l} C_{7} H_{16} (l) + 11 O_{2} (g) \to 7 C O_{2} (g) + 8 H_{2} O (l) \\ Δ n_{g} = n_{p} - n_{r} = 7 - 11 = - 4 \\ Δ H = Δ U + Δ n_{g} R T \\ Δ H - Δ U = - 4 R T \end{array}$

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