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Q.

The difference between threshold wavelengths for two metal surfaces A and B having work  function ϕA=9 eV    and  ϕB=4.5 eV   in nm is (Given, hc = 1246 eV-nm)

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a

264

b

138

c

540

d

276

answer is D.

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Detailed Solution

Given,  ϕA=9eV  ϕB=45eV
Threshold wavelength of metal surface, A
λA=1242ϕAnm=12429nm  
Similarly,  λB=12424.5   λBλA12404.5=12409
                    
                                = 275.55 – 137.77
                                = 137.78 – 138 nm 
 

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