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The difference between $∆ E$ and $∆ H$ (on a molar basis) for the combustion of n-octane (l) at 25°C would be

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-13.6 kJ

– 11.15 kJ

-1.14 kJ

+11.15 kJ

answer is C.

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Detailed Solution

$ΔH - ΔE = ΔnRT$

C₈H₁₈(g)+ 25/2 O₂(g)→8CO₂(g)+9H₂O(g)

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