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Q.

The difference between $Δ_{r} H$ and $Δ_{r} U$ of the reaction $2 C_{6} H_{6} (l) + 15 O_{2} (g) ⟶ 12 {CO}_{2} (g) + 6 H_{2} O (l)$ at $27^{\circ} C$ is

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a

$- 7.48 kJ {mol}^{- 1}$

b

$7.48 kJ {mol}^{- 1}$

c

$3.74 kJ {mol}^{- 1}$

d

$- 14.96 kJ {mol}^{- 1}$

answer is A.

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Detailed Solution

$Δ_{r} H - Δ_{r} U = (Δ v_{g}) R T = (- 3) (8.314 {JK}^{- 1} {mol}^{- 1}) (300 K) = - 7483 J {mol}^{- 1}$

Thus the option A is correct.

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The difference between ΔrH and ΔrU of the reaction 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l) at 27∘C is