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Q.

The difference of speed of light in the two media A and B $(v_{A} - v_{B})$ is $2.6 x 10^{7} m / s$ . If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 x 10⁸ ms^-1)

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a

1.318

b

1.13

c

0.12

d

1.303

answer is C.

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Detailed Solution

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$v = \frac{c}{μ}$

$\Rightarrow v_{B} = \frac{3 x 10^{8}}{1.47} = 2.04 x 10^{8} m / s$

$∵ v_{A} - v_{B} = 2.6 x 10^{7} m / s$

$v_{A} = 23 \times 10^{7}$

$∴ \frac{μ_{B}}{μ_{A}} = \frac{v_{A}}{v_{B}} = \frac{23 x 10^{7}}{20.4 x 10^{7}} = 1 . 13_{}$

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The difference of speed of light in the two media A and B (vA - vB) is 2.6 x 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 x 108 ms-1)