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Q.

The difference of speed of light in the two media A and B(v_A - v_B) is 2 x 10⁷ m/s . If the refractive index of medium B is 1.5, then the ratio of refractive index of medium B to medium A is: (Given: speed of light in vacuum C = 3 x 10⁸ ms^-1)

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a

1.25

b

2

c

0.8

d

1.8

answer is D.

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Detailed Solution

$\begin{array}{l} V_{A} - V_{B} = 5 \times 10^{7} {ms}^{- 1} \\ But V_{B} = \frac{C_{0}}{μ_{B}} = \frac{3 \times 10^{8}}{1.5} = 2 \times 10^{8} {ms}^{- 1} \\ \Rightarrow V_{A} = 2.5 \times 10^{8} {ms}^{- 1} \\ But \frac{μ_{B}}{μ_{A}} = \frac{V_{A}}{V_{B}} = \frac{2.5}{2} = 1.25 \end{array}$

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