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Q.

The difference of two natural numbers is 3 and the difference of their reciprocals is  3 28  Find the numbers.


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a

12 and 14

b

10 and 11

c

4 and 7

d

5 and 7 

answer is C.

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Detailed Solution

Given: The difference of two natural numbers is 3 and the difference of reciprocals is 3 28   Assume that the natural numbers are ‘a’ and ‘b’.
According to the question,
ab =3 a =b+3 And, 1 b 1 a = 3 28 1 b 1 (b+3) = 3 28  
b+3b b(b+3) = 3 28 3b(b+3) =84 3 b 2 +9b =84 b 2 +3b28 =0  
b 2 +7 b4 b28=0  b( b+7)4( b+7)=0 ( b4)(b+7)=0  
Either b − 4 = 0 or b + 7 = 0
b=4 b=7  
Neglect b = −7 case since −7 is not a natural number.
b =4 a =b+3 a =4+3 a =7  
Hence, 4 and 7 are the two natural numbers whose difference is 3 and the difference of their reciprocals is 3 28   .
So, the correct option is 3.
 
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