The differential equation at the Family at curves y=ax+1a where a≠0 is an arbitrary constant, has the degree

y=ax+1adydx=aEliminating ‘a’ from (1) & (2) we gety=xdydx+1dydx⇒y(dydx)=x(dydx)2+1∴ Degree ‘2’

The differential equation at the Family at curves y=ax+1a where a≠0 is an arbitrary constant, has the degree

y=ax+1adydx=aEliminating ‘a’ from (1) & (2) we gety=xdydx+1dydx⇒y(dydx)=x(dydx)2+1∴ Degree ‘2’

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The differential equation at the Family at curves $y = a x + \frac{1}{a}$ where $a \neq 0$ is an arbitrary constant, has the degree

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$y = a x + \frac{1}{a}$

$\frac{d y}{d x} = a$

Eliminating ‘a’ from (1) & (2) we get

$y = x \frac{d y}{d x} + \frac{1}{\frac{d y}{d x}}$

$\Rightarrow y (\frac{d y}{d x}) = x {(\frac{d y}{d x})}^{2} + 1$

$∴$ Degree ‘2’

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The differential equation at the Family at curves y=ax+1a where a≠0 is an arbitrary constant, has the degree

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The differential equation at the Family at curves $y = a x + \frac{1}{a}$ where $a \neq 0$ is an arbitrary constant, has the degree