The differential equation  $\frac{dy}{dx}=\frac{7x-3y-7}{-3x+7y+3}$

reduces to homogeneous form by making the substitution 

Let $x=X+h,y=Y+k\text{. }$ Then, the given equation becomes 

$\frac{dY}{dX}=\frac{(7X-3Y)+(7h-3k-7)}{(-3X+7Y)+(-3h+7k+3)}$

This will reduce to a homogeneous differential equation, if 

$7h-3h-7=0$and $-3h+7k+3=0\Rightarrow h=1,k=0$

Hence, $x=X+1,y=Y+0$ reduces the given equation to homogeneous form.