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Q.

The digit at the unit place of sum  (1!)2+(2!)2+(3!)2+(4!)2++(2008!)2
 is 

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a

7

b

0

c

3

d

4

answer is C.

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Detailed Solution

 Let S=1+4+36+576+.+(2008!)2

=617+all other terms end with ‘O’ the digit at unit place = 7

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