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Q.

The dimension of ( 1/2) ε0E2ε0: permittivity of free space; E : electric field) is :

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a

[ML2T-1]

b

[MLT-2]

c

ML-1T-2

d

[MLT-1]

answer is B.

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Detailed Solution

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  Energy per unit volume = energy density due to electric field =E202

                                                                                                 =M L2T-2L3= M L-1T-2

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