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Q.

The dimension of $\frac{B^{2}}{2 μ_{0}}$ , where B is magnetic field and $μ_{0}$ is the magnetic permeability of vacuum, is:

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a

$M L^{- 1} T^{- 2}$

b

$M L^{2} T^{- 2}$

c

$M L^{2} T^{- 1}$

d

$M L T^{- 2}$

answer is A.

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Detailed Solution

Energy density in magnetic field $= \frac{B^{2}}{2 μ_{0}}$

$= \frac{Force \times displacement}{{(displacement)}^{3}} = \frac{M L T^{- 2} L}{L^{3}} = M L^{- 1} T^{- 2}$

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The dimension of B22μ0, where B is magnetic field and μ0 is the magnetic permeability of vacuum, is: