The dimension of stopping potential $V_0$  in photoelectric effect in units of Planck’s constant ‘h’, speed of light ‘C’ and universal gravitational constant ‘G’ and ampere A is:

$V=K{\left(h\right)}^a{\left(A\right)}^b{\left(G\right)}^c{\left(C\right)}^d$  (V is voltage)
We know  $\left[h\right]=M{L}^2{T}^{-1}$
[A] = $A$
[G] = $M^{-1}{L}^3{T}^{-2}$
[C] = $L{T}^{-1}$
[V] =   ${\text{ML}}^{\text{2}}{\text{T}}^{\text{-3}}{\text{A}}^{-1}$
  

comparing dimensions on both sides,

 ${\text{ML}}^{\text{2}}{\text{T}}^{\text{-3}}{\text{A}}^{-1}\text{ = }{\left(M{L}^2{T}^{-1}\right)}^a{\left(A\right)}^b{\left(M^{-1}{L}^3{T}^{-2}\right)}^c{\left(L{T}^{-1}\right)}^d$
 ${\text{⇒ML}}^{\text{2}}{\text{T}}^{\text{-3}}{\text{A}}^{-1}= M^{a-c}{L}^{2a+3c+d}{T}^{-a-2c-d}{A}^b$

Comparing the powers, 
 $a-c=\mathrm{1..................}\left(1\right)$
$b=-\mathrm{1.................}\left(2\right)$

$\begin{array}{l}-a-2c-d = -3 \mathrm{.........}\left(3\right)\text{}\\ 2a+3c+d = 2 \mathrm{.............}\left(4\right)\end{array}$

$\begin{array}{l}Add 3 and 4 , \\ \text{}a+c = -1 \mathrm{.........}\left(5\right)\text{}\\ \text{}Add 1 and 5 , \text{}\\ 2a =0\text{}\\ \Rightarrow a=0\text{}\\ \therefore c=-1\text{}\\ \text{}Put values of a and c in 3,\\ \text{}2-d=-3\text{}\\ \Rightarrow d=5\text{}\\ Thus, V=K h^0{A}^{-1}{G}^{-1}{C}^5\text{}\end{array}$