Book Online Demo

Check Your IQ

Try Test

Courses

The dimension of the metallic cuboid is $30 cm \times 20 cm \times 15 cm$ and its mass is $30 kg$ . If $g = 10 m / s^{2}$ then what is the pressure exerted by the cuboid when it is resting on the face having $20 cm \times 15 cm$ on the table?

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

P = 10^{4} pa

P = 10^{6} pa

P = 10^{9} pa

P = 10^{2} pa

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The dimension of the metallic cuboid is

30 cm \times 20 cm \times 15 cm

and its mass is

30 kg

. The pressure exerted by the cuboid when it is resting on the face having

20 cm \times 15 cm

on the table is

P = 10^{4} pa

.
Given that, to calculate the pressure of a cuboid face with dimensions

20 cm \times 15 cm

\Rightarrow A = 20 cm \times 15 cm

\Rightarrow = 300 \times 10^{- 4} m^{2}

Pressure is defined as the force per unit area.

Pressure (P) = \frac{Force (F)}{Area (A)}

Force acting block on the surface of the table,

F = mg

m

is the mass and

g

is the acceleration due to gravity.
Here the pressure exerted on an area

A

for an object of mass

m

\Rightarrow P = \frac{mg}{A}

g

is acceleration due to gravity of earth.

\Rightarrow P = \frac{30 kg \times 10 m / s^{2}}{300 \times 10^{- 4} m^{2}}

\Rightarrow P = 10^{4} kg / m s^{2}

\Rightarrow P = 10^{4} pa

Hence the pressure exerted by the cuboid is

10^{4} pa

Watch 3-min video & get full concept clarity