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The dimension of the metallic cuboid is $30 cm \times 20 cm \times 15 cm$ and its mass is $30 kg$ . If $g = 10 m / s^{2}$ then what is the pressure exerted by the cuboid when it is resting on the face having $20 cm \times 15 cm$ on the table?

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P = 10^{4} pa

P = 10^{6} pa

P = 10^{9} pa

P = 10^{2} pa

answer is A.

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Detailed Solution

The dimension of the metallic cuboid is

30 cm \times 20 cm \times 15 cm

and its mass is

30 kg

. The pressure exerted by the cuboid when it is resting on the face having

20 cm \times 15 cm

on the table is

P = 10^{4} pa

.
Given that, to calculate the pressure of a cuboid face with dimensions

20 cm \times 15 cm

\Rightarrow A = 20 cm \times 15 cm

\Rightarrow = 300 \times 10^{- 4} m^{2}

Pressure is defined as the force per unit area.

Pressure (P) = \frac{Force (F)}{Area (A)}

Force acting block on the surface of the table,

F = mg

m

is the mass and

g

is the acceleration due to gravity.
Here the pressure exerted on an area

A

for an object of mass

m

\Rightarrow P = \frac{mg}{A}

g

is acceleration due to gravity of earth.

\Rightarrow P = \frac{30 kg \times 10 m / s^{2}}{300 \times 10^{- 4} m^{2}}

\Rightarrow P = 10^{4} kg / m s^{2}

\Rightarrow P = 10^{4} pa

Hence the pressure exerted by the cuboid is

10^{4} pa

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