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Q.

The dimensional formula for magnetic field vector is

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a

$[M^{1} A^{1} T^{- 2}]$

b

$[M^{1} A^{- 1} T^{2}]$

c

$[M^{- 1} A^{- 1} T^{2}]$

d

$[M^{1} A^{- 1} T^{- 2}]$

answer is A.

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Detailed Solution

$\bar{B} = \frac{\bar{F}}{qv} = \frac{\bar{F}}{(it) v} = \frac{M L T^{- 2}}{A \times T \times L T^{- 1}} = [M^{1} A^{- 1} T^{- 2}]$

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