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Q.

The dimensional formula of gravitational constant is

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a

${ML}^{2} T^{- 1}$

b

$M^{- 1} L^{3} T^{- 2}$

c

$M^{- 2} L^{2} L^{- 1}$

d

$M^{- 2} L^{3} T^{- 2}$

answer is A.

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Detailed Solution

Gravitation constant
$\begin{array}{l} G = \frac{{Fr}^{2}}{{kg}^{2}} \\ G = \frac{N \cdot M^{2}}{{kg}^{2}} \\ DF - M^{- 1} L^{3} T^{- 2} \end{array}$

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