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Q.

The dimensions of a field are 15m by 12m. A pit 7.5m long, 6m wide and 1.5m deep is dug at one corner of the field. The earth removed is evenly spread over the remaining area of the field. Calculate the rise in the level of the field.


Sub Grade: 9


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a

0.5m

b

2m

c

4m

d

0.25m 

answer is A.

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Detailed Solution

Volume of phl = l*b*h
⇒Y = 6m*7.5m*1.5m
⇒Y = 67.5m3
Area of field
A field = l*b
= 12*15
= 180 m2
⇒Area cof plate= 7.5*6
Aplt = 45 m2
Now remaining area
⇒A = a field - plt
⇒A = 180-45
⇒A = 135 m2
⇒Let h be the use in level of the field
⇒V = A*h
⇒67.5= 135*h
⇒h= 67.5/135
⇒h= 0.5 m
⇒The risein level of the field is 0.5 m
     
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