The dimensions of a rectangular block measured with a vernier callipers having least count of $0.1 mm$is$5mm\times 10mm\times 5mm.$  The maximum percentage error in measurement of volume of the block is

V=xyz

Where x,y and z are the three dimensions then $\begin{array}{l}\left(\frac{\Delta V}{V}\right)=\left(\frac{\Delta x}{x}+\frac{\Delta y}{y}+\frac{\Delta z}{z}\right)\\ or\left(\frac{\Delta V}{V}\right)X100=\left(\frac{\Delta x}{x}+\frac{\Delta y}{y}+\frac{\Delta z}{z}\right)\text{\hspace{0.17em}×}100\\ =\left(\frac{0.1}{5}+\frac{0.1}{10}+\frac{0.1}{5}\right)\text{×}100\\ =5\%\end{array}$