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Q.

The dimensions of a rectangular box are in the ratio of 2:3:4 and the difference between the cost of covering it with sheet of paper at the rates of Rs.8 and Rs.50 per sq. m is Rs. 1248. Find the dimensions of the box.


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a

Length is 8 m  , breadth is 12 m  and height is 16 m  

b

Length is 12 m  , breadth is 16 m  and height is 8 m  

c

Length is 8 m  , breadth is 8 m  and height is 12 m  

d

Length is 16 m  , breadth is 12 m  and height is 8 m   

answer is A.

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Detailed Solution

Given, dimensions of a rectangular box in the ratio of 2:3:4.
 The difference between the cost of covering box with sheet of paper at the rates of Rs.8 and Rs.50 per sq. m is Rs. 1248.
Consider the length be 2x, breadth be 3x and height be 4x.
Surface area of the box is given by S=2 lb+bh+lh  
Substituting the values and simplify,
  S=2 2x×3x+3x×4x+2x×4x S=2 6 x 2 +12 x 2 +8 x 2 S=2×26 x 2 S=52 x 2  
The cost for the paper at a rate Rs.8 =52 x 2 ×8  
Cost for the paper at a rate Rs.8=416 x 2  
Cost for the paper at a rate Rs.9.50 =52 x 2 ×9.50  
  Cost for the paper at a rate Rs.9.50=494 x 2  
Now calculating the difference of the cost and equate it with Rs.1248,
494 x 2 416 x 2 =1248  
Simplify the term,
78 x 2 =1248  
x 2 = 1248 78  
x 2 =16   x= 16 x=4  
Substitute the value of x   to calculate the length,
  l=2x l=2×4 l=8m  
Substitute the value of x   to calculate the breadth,
  b=3x b=3×4 b=12m  
Substitute the value of x   to calculate the height,
h=4x h=4×4 h=16m   So, the length is 8 m   , breadth is 12 m   and height is 16 m   .
Hence option (1) is correct.
 
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