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The dimensions of $σ b^{4}$ ( $σ$ = Stefan’s constant and b= Wien’s constant ) are:

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$[M L^{4} T^{- 3}]$

$[M^{0} L^{0} T^{0}]$

$[M L^{- 2} T^{- 3}]$

$[M L T^{- 2}]$

answer is B.

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Detailed Solution

SI unit of $σ = \frac{w}{m^{2} k^{4}}$
SI unit of $b = m k$
$σ b^{4} = \frac{w}{m^{2} k^{4}} \times m^{4} k^{4} = M L^{4} T^{- 3}$

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